Question

What is the mass, in grams, of 28.80 ml of acetone?

Answer 1

density of acetone in gm/cm^3 is 0.791

=28.80cm^3*0.791 g/cm63

=22.78 g

Answer 2

The given question is incomplete. The complete question is as follows.

What is the mass, in grams, of 28.80 ml of acetone? Acetone (nail polish remover) has a density of 0.7857
`g/cm^(3)`.

Step-by-step explanation:

It is known that density is the mass of a substance occupied in per unit volume of the object.

Mathematically, Density =
`(mass)/(volume)`

Therefore, putting the given values into the above formula as follows.

Density =
`(mass)/(volume)`

0.7857
`g/cm^(3)` =
`(mass)/(28.80 m^(3))` (1 ml = 1
`m^(3)`)

mass = 22.62 g

Thus, we can conclude that mass of given acetone is 22.62 g.