Question

which values must be added to both sides of the equation x^2-3/4x=5 to make it a perfect square trinomial?

Answer 1

So to find the constant of a perfect square, divide the x coefficient by 2 and then square that quotient.

*Remember that dividing by a number is the same as multiplying by the reciprocal.

`-(3)/(4)* (1)/(2)=-(3)/(8)\\\\(-(3)/(8))^2=-(3)/(8)*-(3)/(8)=(9)/(64)`

You need to add 9/64 on both sides of the equation for this to be a perfect square.