Question

Use an algebraic equation to solve the problem. a rectangle is 3 times as long as it is wide. the perimeter is 60 cm. find the dimensions of the rectangle. round to the nearest tenth if necessary.

Answer 1

It is given in the question that a rectangle is 3 times as long as it is wide. the perimeter is 60 cm.

Let the width of the rectangle be x cm. And length is 3 times of width, therefore length is 3x cm .

And perimeter is the sum of all sides. That is

`x+3x+x+3x=60`

`8x=60`

Dividing both sides by 8,

`x= 7.5cm`

Therefore width is 7.5 cm and length is 3 times of it, that is length is 22.5 cm .