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sum of the angle measures of a triangle is 180° suppose that one angle in a triangle has a degree measure of 4X -3 and another has a degree measure of 6X -6 write an expression for the degree measure of the third angle in the triangle

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Total sum of angles of a triangle is equal to 180 degrees.

First angle = 4x-3 degrees.

Second angle = 6x-6 degrees.

Let the third angle be represented by
\beta


4x-3 + 6x-6 +\beta =180

Add all the terms with x together and all the constants together.


(4x+6x) + ( -3 -6 ) + \beta  = 180


10x -9 +\beta = 180


\beta = 180 - 10x+ 9

Third angle
\beta = 189 -10x .... Answer

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