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Which is a correct factorization of 391? A.(20 - 3)2 B.(20 - 3)(20 + 3) C.(20 - 9)(20 + 9) D.(20 + 3)2

Which is a correct factorization of 391? A.(20 - 3)2 B.(20 - 3)(20 + 3) C.(20 - 9)(20 + 9) D.(20 + 3)2
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Which is a correct factorization of 391?

A.(20 - 3)2
B.(20 - 3)(20 + 3)
C.(20 - 9)(20 + 9)
D.(20 + 3)2

asked
User Hisham Hijjawi
by
8.3k points

2 Answers

1 vote
the answer is c
(20x20)+(20x9)-(9x20)-(9x9)
=391
answered
User Amomum
by
7.8k points
3 votes

The answer is option B.

Because (20 - 3) (20 + 3)

= (20)^2 - 3^2

=400 - 9

=391.

answered
User Fabio Lolli
by
8.0k points
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