Question

The perimeter of a rectangle is 62 feet the width of the rectangle is 5 feet less than twice its length find the area of the rectangle

Answer 1

Perimeter = 62 feet

Width = 2(X*2 - 5) + 2x = 62

4x - 10 + 2x = 62

6x - 10 = 62

6x = 72

x = 12

Length = 12

Width = 12 * 2 - 5 = 19

19 * 12 = 228 ftx^{2}