Question

What is the answer if the sum of three numbers is 95 and the second number is three less than twice the first number and the third number is is ten less than three times the second?

Answer 1

n + (2n - 3) + [3(2n - 3) - 10] = 95

n + (2n - 3) + [6n - 9 - 10] = 95

n + (2n - 3) + (6n - 19) = 95

n + 2n - 3 + 6n - 19 = 95

9n - 22 = 95

9n - 22 + 22 = 95 + 22

9n = 95 + 22

9n = 117

9n/9 = 117/9

n = 13