Question

A honeybee flaps its wings 200 times per second.how much time is required for one wingbeat? give your answere in millisecond

Answer 1

The time required for one wing beat is 5 milliseconds.

Step-by-step explanation

Lets assume, the time required for one wing beat is
`t` seconds

So, the time required for 200 wing beat
`= 200t` seconds

Given that, the honeybee flaps its wings 200 times per 1 second. So...

`200t=1 \\ \\ t=(1)/(200)seconds\\ \\ t= ((1)/(200)*1000 )milliseconds\\ \\ t=( 5 )milliseconds`

So, the time required for one wing beat is 5 milliseconds.