Question

64^1/3=4 in logarithmic form

Answer 1

`b^(a) = c \\ \\In\ logarithmic\ form\ it\ can\ be\ written\ as \\ \\log_(b)c=a. \\ \\ So.\ in\ our\ case \\ \\64^{(1)/(3)}=4 \\ \\ log_(64)4=(1)/(3)`