Question

Assume the weight of a randomly chosen american passenger car is a uniformly distributed random variable ranging from 2,500 pounds to 4,500 pounds. (a) what is the mean weight of a randomly chosen vehicle?

Answer 1

Let X= weight of the passenger car

a/q, X is u(2500,4500)

we know that mean= a+b/2

so a=2500, b=4500

hence, mean=2500+4500/2

=3500 pounds