Question

A right triangle has an area of 2k^2-k-15 One of the legs has a length of k^2-9 What is the ratio of the area of a triangle to the leg?

Answer 1

Given

A = 2k² -k -15

L = k² -9

Find

A/L

Solution

`\displaystyle(A)/(L)=(2k^2-k-15)/(k^2-9)=((k-3)(2k+5))/((k-3)(k+3))\\\\=(2k+5)/(k+3)`