Given: PQ=2x-3. if QR=5x+7 and PR=10x-11
To Find: PR
Solution: From the attached diagram, point P, Q and R are co-linear.
Hence, PR = PQ + QR
or, 10x-11 = 2x-3 + 5x+7
or, 10x - 7x = 15
or, x = 5
Now, we shall calculate the value of PR
PR = 10x-11
or, PR = 10× 5 - 11
or, PR = 39
Hence, the required value of PR will be 39.