Question

If one mole of acetone has a mass of 58.1 g, what is the mass of 0.015 millimoles (mmol) of the acetone? express your answer in nanograms using the correct number of significant figures.

Answer 1

The mass of 0.015 millimoles of acetone is -300,000 nanograms.

Step-by-step explanation:

To find the mass of 0.015 millimoles (mmol) of acetone, we can use the molar mass of acetone and the given number of moles. The molar mass of acetone is 58.1 g/mol, so the mass of 1 mole of acetone is 58.1 g.

Since 0.015 mmol is a very small fraction of a mole, we would expect the mass to be about one-ten thousandth of the molar mass, which is -0.02 g.

In nanograms, the mass of 0.015 mmol of acetone is -0.02 g x 1,000,000,000 ng/g x 0.015 mmol/mol = -300,000 ng.

Answer 2

1 mole of acetone has a mass of 58.1 g thus, molar mass of acetone is 58.1 g/mol. Number of mole can be converted into mass as follows:

`m=n* M` ...... (1)

Here, n is number of mole, m is mass and M is molar mass.

First convert milimole to mole as follows:

`1 mmol=10^(-3)mole`

Thus,

`0.015 mmol=0.015* 10^(-3) mol=1.5* 10^(-5) mol`

Putting the values in equation (1)

`m=n* M=1.5* 10^(-5)mol* 58.1 g/mol=8.71* 10^(-4)g`

Converting grams into nano grams:

`1 g=10^(9)nanogram`

Thus,

`8.71* 10^(-4)g=8.71* 10^(-4)* 10^(9) g=8.71* 10^(5) nanograms`

Thus, the mass of acetone is
`8.71* 10^(5)` nano grams.