Question

the length of a rectangle is one more than four times its width. if the perimeter of the rectangle is 62 meters, find the dimensions of the rectangle

Answer 1

Length (L): 4w + 1

width (w): w

Perimeter (P) = 2L + 2w

62 = 2(4w + 1) + 2(w)

62 = 8w + 2 + 2w

62 = 10w + 2

60 = 10w

6 = w

Length: L = 4w + 1 → 4(6) + 1 → 24 + 1 → 25

Answer: 6 x 25

Answer 2

Length of the rectangle = 25 m

width of the rectangle = 6 m

Explanation:

Let x be the length of the rectangle and w be the width

the length of a rectangle is one more than four times its width

`l=4w+1`

Perimeter of rectangle = 2 times length + 2 times width

`Perimeter = 2(l) +2(w)`

`62=2(4w+1)+2w`

`62=8w+2+2w`

`62=10w+2`

Subtract 2 from both sides

`60=10w`

Divide by 10 on both sides

`6=w`

So width of the rectangle = 6 m

Length is
`l=4w+1`

`l=4(6)+1=25`

Length of the rectangle = 25 m