Question

what volume, in liters, will 6.32 × 10^2 of air occupy if the density of air is 1.29 g/L? Express your answer in scientific notation.

Answer 1

4.90× 10^2 L

I am guessing that the mass of the air is 6.32 × 10^2 g. Then,

Volume = 6.32 × 10^2 g × (1 L/1.29 g) = 4.90× 10^2 L

Answer 2

Step-by-step explanation:

It is known that density is amount of mass present in per unit volume of the substance.

Mathematically, Density =
`(mass)/(volume)`

It is given that mass is
`6.32 * 10^(2) g` and density is 1.29 g/L.

Therefore, calculate the volume by putting the given values into the above formula as follows.

Density =
`(mass)/(volume)`

1.29 g/L =
`(6.32 * 10^(2) g)/(volume)`

volume = 489.92 L

Thus, we can conclude that volume of the air is 489.92 L.