Question

A fair coin is tossed three three times in succession. the set of equally likely outcomes is startset hhh comma hht comma hth comma thh comma htt comma tht comma tth comma ttt endset{hhh, hht, hth, thh, htt, tht, tth, ttt}. find the probability of getting exactly one tail.

Answer 1

Solution: We are given that a fair coin is tossed three times. The sample space associated with the three tosses of fair coin is:

`S=\left \{ HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\right \}`

We have to find the probability of getting exactly one tail.

From the above sample space, we clearly see there are three outcomes which favors the probability of exactly one tail.

n( 1 tail) =
`\left \{HHT,HTHTHH \right \}`

Therefore the probability of exactly one tail is

`(3)/(8) =0.375`