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) a rectangle has perimeter 40 feet and an area of 96 square feet. find the dimensions of the rectangle assuming the width is smaller than the length.

asked
User Bivas
by
8.2k points

1 Answer

3 votes

w=P

4+1

4P2﹣16A=40

4+1

4·402﹣16·96=12ft

w=P

4﹣1

4P2﹣16A=40

4﹣1

4·402﹣16·96=8ft

answered
User Panjo
by
7.8k points

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