Question

A rocket traveling at 88 m/s is accelerated uniformly to 132 m/s over a 15 s interval. what is its displacement during this time?

Answer 1

First of all, we can find the acceleration of the rocket, which is given by:

`a=(v-u)/(t)`

where v is the final velocity of the rocket, u its initial speed, and t the time interval. Plugging in the data of the problem, we find

`a=(132 m/s-88 m/s)/(15 s)=2.93 m/s^2`

And now we can find the displacement of the rocket using the following equation:

`S=ut+(1)/(2)at^2=(88 m/s)(15 s)+(1)/(2)(2.93 m/s^2)(15 s)^2 =1649.6 m`