Question

Evaluate 3x+4(y+3) when x is 5 less than the quotient of y and 3, and y=18.

Answer 1

It is given that x is 5 less than the quotient of y and 3.

And given value of y is 18 .

So quotient of y and 3 is

`(18)/(3) = 6`

And 5 less than 6 =1

So we have y=18 and x=1

Given expression is

`3x+4(y+3)`

At x=1 and y=18, we will get

`3(1)+4(18+3) =3 + 4(21)`

`= 3+84=87`