Question

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?

A. `4/11`
B. `7/11`
C. `3/11`
D. `2/3`

Answer 1

7/11

Explanation:

Answer 2

The total flowers is 4 + 3 + 4 = 11

4 roses + 3 carnations = 7

Probability of picking either a rose or a carnation = 7/11