6 ≤ 5(x - 4) -2(-x + 1)
First, distribute 5 to all terms within the first parenthesis, and -2 to all terms in the second parenthesis
6 ≤ (5x - 20 + 2x -2)
Combine like terms
6 ≤ (5x + 2x - 20 - 2)
6 ≤ 7x - 22
Isolate the x. Do the opposite of PEMDAS. Note that what you do to one side you to the other.
Add 22 to both sides
6 (+22) ≤ 7x - 22 (+22)
28 ≤ 7x
Divide 7 from both sides
28/7 ≤ 7x/7
28/7 ≤ x
4 ≤ x is your answer
Use a closed dot (because of the equal underneath) on 4, and go left with an arrow
hope this helps