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One number is 7 more than another number. The sum of the numbers is 63. What is one of the numbers

asked
User Mene
by
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2 Answers

4 votes

Hello,

n + ( n + 7 ) = 63

n + n + 7 = 63

2n + 7 = 63

2n = 63 - 7 = 56

n = 56 / 2 = 28

n + 7 = 28 + 7 = 35

35 + 28 = 63

Bye :)

answered
User Arxoft
by
8.6k points
6 votes

let one number = x, let another number = y

x = y + 7 , x + y = 63

Plug in y + 7 for x

(y + 7) + y = 63

Simplify

2y + 7 = 63

Isolate the y. Note the equal sign. What you do to one side you do to the other

2y + 7 (-7) = 63 (-7)

2y = 56

2y/2 = 56/2

y = 28

As you are only asking for one of the numbers, 28 is your answer. The other is 35.


hope this helps

answered
User Zach Inglis
by
8.2k points

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