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asked Oct 21, 2019 73.7k views

1 Answer

Ross Halliday · Answer 1 · 2019-10-27T18:58:07+0000

Your equation is

(x-8)^2 = 7

So, you're asking that the left hand side, squared, must be 7.

There are only two possibilities for a number to give 7 then squared: that number is even the square root of 7 or its opposite.

So, one solution is given by
$x-8 = √(7) \implies x = 8+√(7)$ .

The other is given by
$x-8 = -√(7) \implies x = 8-√(7)$ .