How many moles of NaCl are contained in 100.0 mL of a 2.0 M solution?

Question

asked Mar 8, 2019 187k views

1 Answer

Niteria · Answer 1 · 2019-03-12T23:50:29+0000

Answer: -

0.2 moles of NaCl are contained in 100.0 mL of a 2.0 M solution

Explanation: -

Strength of NaCl = 2.0 M

Volume of NaCl solution = 100.0 mL

=
(100)/(1000)

= 0.1 L

Number of moles of NaCl = volume of NaCl x Strength of NaCl

= 0.1 L x 2.0 M

= 0.2 moles

0.2 moles of NaCl are contained in 100.0 mL of a 2.0 M solution