Question

Applying the concept. Distance formula/ midpoint formula. Not sure how to figure this one out. or if I need to use one of the formulas.

Answer 1

(2 - 5)^2 + (y - 1)^2 = 5^2 --> y = -3 ∨ y = 5

The points are: (2, -3) ; (2, 5).

Answer 2

(2 - 5)^2 + (y - 1)^2 = 5^2 --> y = -3 ∨ y = 5

The points are: (2, -3) ; (2, 5).