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2 votes
Oxidation of h2c2o4 to co2 with mno4 how many moles of electrons

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User Osse
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1 Answer

5 votes
Assuming the manganese IV oxide is being reduced to a manganese II ion, the answer is 10 moles of electrons.

Oxidation: 5[ C2O4(2-) -> 2 CO2 + 2e- ]
Reduction: 2[ MnO4 + 5e- + 8H+ -> Mn(2+)
+ 4H2O ]
answered
User Yellowbuck
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8.6k points
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