Question

A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T. What is the magnitude of the magnetic force acting on the charge? 1.6 × 10–1 N 6.0 × 10–1 N 1.6 × 105 N 6.0 × 105 N

(please show your work in solving this)

Answer 1

1.6 × 10–1 N

Step-by-step explanation:

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Answer 2

Force on a moving charge is given by

`F = q(v x B)`

Given that

q = 6.8 C

`v = 6.5 * 10^4 m/s`

B = 1.4 T

angle = 15 degree

`F = qvB sin\theta`

`F = 6.8*6.5 * 10^4 * 1.4 * sin15`

`F = 1.6 * 10^5 N`