Question

What is the molarity of an 18 L solution with 64 grams of sodium chloride dissolved in it?

Answer 1

Molarity = moles of solute / liter of solution

in your case ,

1) liter of solution is = 18 L

2) mole of solute(NaCl) = gram/molar mass = 64/58.44= 1.095

Now you can put both values from 1 and 2 in the first equation to calculate the Molarity

Answer 2

Answer: 0.06 M

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

`Molarity=(n)/(V_s)`

where,

n= moles of solute
`NaCl`

`Moles=\frac{\text{Given mass}}{\text{Molar mass}}=(64g)/(58.5g/mol)=1.09moles`

`V_s` = volume of solution in Liters = 18 L

Putting in all the values we get,

`Molarity=(1.09moles)/(18L)=0.06M`

Thus the molarity of solution is 0.06 M