Question

The length of each of the bonds between the atoms of a molecule of nitrogen (n2) is 0.0465 nm. the mass of a nitrogen atom is 2.32 × 10−11 pg. determine the moment of inertia of the molecule about an axis passing through the center of mass perpendicular to the line joining the two atoms

Answer 1

Moment of inertia of N₂ molecule about an axis passing through the center of mass perpendicular to the line joining the two atoms=i=2.51 x 10⁻⁴⁷ kg m²

Step-by-step explanation:

Moment of inertia= i= mr₁²+ mr₂²

m= mass of nitrogen atom=2.32 x 10⁻¹¹pg=2.32 x 10⁻²⁶ Kg

r1= r2=0.0465/2= 0.02325 nm=2.325 x 10⁻¹¹ m

so i= 2.32 x 10⁻²⁶ (2.325 x 10⁻¹¹)²+2.32 x 10⁻²⁶ (2.325 x 10⁻¹¹)²

i=2.51 x 10⁻⁴⁷ kg m²