Question

Ou are given a 25.3 µf capacitor that is connected to a 13.0 v dc power supply. what will be the charge that is stored on this capacitor when it is fully charged?

Answer 1

charge stored in the capacitor=3.29 x 10⁻⁴ C

Step-by-step explanation:

we use the formula

Q= C V

Q= charge

C= capacitor=25.3 μF= 25.3 x 10⁻⁶ F

V= voltage= 13 V

Q=(25.3 x 10⁻⁶ ) (13)

Q= 3.29 x 10⁻⁴ C