Question

3/7(b+2)-6/7(b-2)=
CAN SOMEONE HELP SOLVE?

Answer 1

3/7(b+2)-6/7(b-2)=

`(3)/(7(b+2)) -(6)/(7(b-2))`

Here we find lcd first

lcd = 7(b+2)(b-2)

converting into lcd form we get,

`(3(b-2))/(7(b+2)(b-2)) -(6(b+2))/(7(b-2)(b+2))`

=
`((3b-6))/(7(b+2)(b-2)) -((6b+12))/(7(b-2)(b+2))`

=
`(3b-6-6b-12)/(7(b+2)(b-2))`

=
`(-3b-18)/(7(b+2)(b-2))`