Question

Evaluate 3x^3y-2/5x^-2y^3 for x=2 and y=3

32/405
160/81
2/5

Answer 1

The given expression is

`(3x^3 y^(-2))/(5x^(-2) y^3)`

Given values of x and y are x=2 and y=3

And on substituting these values, we will get

`(3(2)^3 (3)^(-2))/(5(2)^(-2) (3)^3)`

Here we need to convert negative exponents to positive exponent, and for that we need to flip the term with negative exponent .

`(3*2^3*2^2)/(5*3^2*3^3)`

`(2^5)/(5*3^4)=(32)/(405)`

So the correct option is the first option .