asked 141k views
4 votes
Which values of x are solutions to the equation below 15x2 - 56 = 88 + 6x2?

2 Answers

3 votes

values of x are x = 4, -4 hope it helps

answered
User Kkgarg
by
8.4k points
3 votes

Answer: The required values of x are

x = 4, -4.

Step-by-step explanation: We are given to find the values of x that are the solutions to the following equation :


15x^2-56=88+6x^2~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Since the above quadratic equation (i) does not contain term involving x, so we will be solving the equation by square root method.

The solution of equation (i) is as follows :


15x^2-56=88+6x^2\\\\\Rightarrow 15x^2-6x^2=88+56\\\\\Rightarrow 9x^2=144\\\\\Rightarrow x^2=(144)/(9)\\\\\Rightarrow x^2=16\\\\\Rightarrow x=\pm√(16)~~~~~~~~~~~[\textup{taking square root on both sides}]\\\\\Rightarrow x=\pm4.

Thus, the required values of x are

x = 4, -4.

answered
User Peter Kreinz
by
7.1k points
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