Register

Find the center, vertices, and foci of the ellipse with equation x^2/400 + y^2/256=1

Find the center, vertices, and foci of the ellipse with equation x^2/400 + y^2/256=1
asked 114k views
4 votes
Find the center, vertices, and foci of the ellipse with equation x^2/400 + y^2/256=1

asked
User Tavnab
by
7.8k points

2 Answers

6 votes
The center of 400z is the pair of y
answered
User Abl
by
9.0k points
1 vote

Answer:

Center: (0,0); Vertices: (-20,0), (20,0); Foci: (-12,0),(12,0)

Explanation:

answered
User Selwyn
by
7.6k points
← Prev Question Next Question →

Related questions

User InsatiableTraveller
asked Apr 1, 2024 10.1k views
Identify the vertices and the foci of the ellipse. (x^2/18)+(y^2/8)=1
InsatiableTraveller asked Apr 1, 2024
by InsatiableTraveller
8.1k points
2 answers
1 vote
10.1k views
User Artistan
asked Jun 6, 2024 33.3k views
Identify the center, the vertices and the foci of the ellipse x^2+3y^2-6x+6y+6=0
Artistan asked Jun 6, 2024
by Artistan
8.6k points
1 answer
4 votes
33.3k views
User Zadr
asked Aug 28, 2024 85.1k views
Identify the vertices and foci of the ellipse. 9x^2+y^2=18
Zadr asked Aug 28, 2024
by Zadr
8.8k points
1 answer
3 votes
85.1k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!