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(secA+cosA)(secA-cosA)=tan^2A+sin^2A

(secA+cosA)(secA-cosA)=tan^2A+sin^2A
asked 34.6k views
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(secA+cosA)(secA-cosA)=tan^2A+sin^2A

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User Sasuke Uchiha
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1 Answer

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(\sec A+\cos A)(\sec A-\cos A)=\sec^2A-\cos^2A


\sec^2A-\cos^2A=(1+\tan^2A)-(1-\sin^2A)


(1+\tan^2A)-(1-\sin^2A)=\tan^2A+\sin^2A

answered
User Armen Hovhannisian
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