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X2-7x-18÷x2+8x+12 what is it in lowest terms

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(x^2-7x-18)/(x^2+8x+12)=(x^2+2x-9x-18)/(x^2+6x+2x+12)=(x(x+2)-9(x+2))/(x(x+6)+2(x+6))\\\\=((x+2)(x-9))/((x+6)(x+2))=(x-9)/(x+6)

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User Mossaab
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