Question

The equation of the line that goes through the point (6,3) and is perpendicular to the line 2x+4y=5 can be written in the form y=mx+b where

Answer 1

The perpendicular equation is y = 2x - 9.

You can find this by first realizing that perpendicular lines have opposite and reciprocal slopes. So since it starts at -1/2 we flip it and make it a negative and the new slope is 2. Now we can use that and the point to get the y intercept using slope intercept form.

y = mx + b

3 = (2)(6) + b

3 = 12 + b

-9 = b

And now we can use our new slope and new intercept to model the equation.

y = 2x - 9

Answer 2

Hay dear friend

According to the question we know that

y = mx + b


then,


3 = 12 +b

-9 = b

now we can use our new slope and new intercept equation

then,

y = 2x-9

I hope it's help you