Question

Which pair of triangles can be proved congruent by the SAS Postulate?

Answer 1

I think its A the first one

Answer 2

Answer:
`A.\ \triangle{ABX}\cong\triangle{DEX}`

Explanation:

In the given picture , we have given that X is the midpoint of
`\overline{AD}` and
`\overline{BE}` .

i.e. AX = XD and BX=XE (1)

Then in
`\triangle{ABX}` and
`\triangle{DEX}`, we have

`\angle{AXB}\cong\angle{EXD}` [∵ Vertical angles are congruent ]

AX = XD and BX=XE [from (1)]

So by SAS postulate of congruence , we have

`\triangle{ABX}\cong\triangle{DEX}`