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What is the point slope of the line when slope is -4 and the given coordinates are (4,-9)

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The point-slope form of the equation of a straight line is:


y-y_1=m(x-x_1)

We have:


m=-4\\(4;-9)\to x_1=4;\ y_1=-9

Substitute:


y-(-9)=-4(x-4)\\\\\boxed{y+9=-4(x-4)}

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