Water (density = 1 ´ 103 kg/m3) flows at 10 m/s through a pipe with radius 0.030 m. the pipe goes up to the second floor of the building, 2.0 m higher, and the pressure remains …

Question

asked Sep 13, 2019 117k views

1 Answer

Guohua Cheng · Answer 1 · 2019-09-18T17:59:32+0000

density of water =
1000 kg/m^3

velocity of flow =
10 m/s

radius of pipe =
0.030 m

Height of second floor =
2 m

Now we can use here Bernuoli's Equation to find the speed of water flow at second floor

$P_1 + 1/2\rho v_1^2 + \rho g h_1= P_2 + 1/2 \rho v_2^2 + \rho g h_2$

P + 1/2 * 1000 * 10^2 + 1000* 9.8 * 0 = P + 1/2 * 1000 * v^2 + 1000*9.8*2

v = 7.8 m/s

Now in order to find the radius of pipe we can use equation of continuity

A_1 v_1 = A_2 v_2

$\pi *0.030^2 * 10 = \pi * r^2 * 7.8$

r = 0.034 m

So radius of pipe at second floor is 0.034 meter