Question

What is an equation for the line that passes through the points (-3 7) and (3,3)

Answer 1

Hi!

First, we need to find the slope.

Here's the equation to find the slope.

`(y2-y1)/(x2-x1)`

Put in the values and solve.

`(3-7)/(3-(-3))`

`-(4)/(6)`

Simplify

`-(2)/(3)`

Now our equation is

`y=-(2)/(3)x+b`

We need to find b. Do this by putting one of the coordinates into the equation then solving.

`3=-(2)/(3)*3+b`

3=-2-b

5=b

`y=-(2)/(3)x+5`

The answer is 3)
`y=-(2)/(3)x+5`

Hope this helps! :)

-Peredhel

Answer 2

(-3, 7) and (3 , 3)

Slope = (7 - 3)/(-3 - 3) = -4/6 = -2/3

y = mx + b

b= y - mx

b = 3 - (-2/3)(3)

b = 3 + 2

b = 5

Equation

y = -2/3 x + 5

Answer

3) y = -2/3 x + 5