Question

8x^2-x-9=(x+1)(?) missing factor

Answer 1

If you were to factorise 8x² - x - 9 using the factor (x + 1), your other factor would need to be (8x - 9). This is because when you expand
(x + 1)(8x - 9), you get 8x² - 9x + 8x - 9, which simplifies to 8x² - x - 9.
I hope this helps!

Answer 2

8x^2 - x - 9 = (x+1)(8x - 9)

Missing factor: (8x - 9)

Hope it helps