asked 221k views
4 votes
Given the system of equations 2x+5y=21 x+2y=6 what is the value of x

2 Answers

6 votes

2x+5y=21 (1st)

x+2y=6 (2nd)


Multiply (2nd) equation by 2 to eliminate x

2x+4y = 12 (2nd)


Now you have:

2x + 5y =21 (1st)

2x + 4y = 12 (2nd)

--------------------------------subtract

y = 9


Substitute y = 9 into (2nd) equation x+2y=6

x + 2(9) = 6

x + 18 = 6

x = -12


Answer

The value of x is -12

answered
User Andrew Komiagin
by
7.4k points
2 votes

x= -12 this is your answer

answered
User Gang Fang
by
8.6k points

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