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Find an equation of the sphere that passes through the point (4, 3, −5) and has center (3, 6, 1).

1 Answer

3 votes

r^2 = (4-3)^2 + (3-6)^2 + (-5-1)^2


r^2 = 1 + 9 + 36


r = sqrt(46)


The equation is:


(x-3)^2 + (y-6)^2 + (z-1)^2 = sqrt(46)

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User CurlyFire
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