Question

How many moles of O2 should be supplied to burn 1.82 mol of C3H8 (propane) molecules In a camping stove?

Answer 1

C3H8 + 5O2 ------> 3CO2 + 4H2O

from reaction 1 mol 5 mol

given 1.82 mol x mol

x=(1.82*5)/1 = 9.10 mol CO2