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Solve 64^x = 16^x−1.

1. x = −2
2 x = −1
3. x = - 1 /4
4. x = negative 1 over 3

asked
User Lastarr
by
8.5k points

2 Answers

4 votes

I am assuming that x - 1 is the exponent of 16


64^x = 16^(x-1)


4^3x = 4^(2x-2)


3x = 2x - 2


x = -2 answer

answered
User MohyG
by
7.8k points
4 votes


64^x = 16^(x-1) \\\\ (4^3)^x=(4^2)^(x-1) \\\\ 4^(3x)=4^(2x-2)\\\\ 3x=2x-2 \\\\ \boxed{x=-2}

answered
User Mjswensen
by
7.7k points

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