Find two consecutive integers such that the larger is nine more than twice the smaller

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asked Feb 10, 2019 70.1k views

1 Answer

Edward A · Answer 1 · 2019-02-15T23:04:21+0000

a=b+1
a=2b+9

b+1=2b+9
-b from both sides
1=b+9
-9 from both sides
-8=b

b+1
-8+1
-7

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2b+9
2(-8)+9
-16+9
-7

The smaller is -8 and the larger is -7

Find two consecutive integers such that the larger is nine more than twice the smaller

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