Answer: The pOH is: " 2.40 " .
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The pOH value of a 0.0010 M solution of calcium hydroxide;
Ca(OH)₂ ; is:
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" 2.40 " .
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Step-by-step explanation:
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Calculate the pOH of a 0.0010 M solution of Ca(OH)₂ .
Note that:
"M" represents the concentration in "Molarity" ;
(that is; "moles of solute per Liter of solution" ; or, "mol / L " } ;
and that for our purposes, anything notes in "brackets" refers to "concentration"; in "M" {"Molarity" ; as explained above.}.
Note that "calcium hydroxide", that is; " Ca(OH)₂ " ;
→ dissociates into the following ions, as follows:
→ Ca(OH)₂ → Ca²⁺ + 2 OH⁻ ;
Therefore, the [OH⁻] equals: {2 * 0.0010} M = 0.0040 M .
For every Ca(OH)₂ you produce 2 OH⁻ .
Note: pOH = - log [OH⁻] ;
pOH = - log ( 0.0040) = 2.3979400086720375 ;
→ round to: " 2.40 " .
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Answer: The pOH is: " 2.40 " .
__________________________________________________________
The pOH value of a 0.0010 M solution of calcium hydroxide; Ca(OH)₂ ; is:
" 2.40 " .
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