In triangle ABC below, sinC=h/a and sinA=h/c. Which of the following combines the two sine ratios into one equation? A. asinC=csinA B. hsinC=hsinA C. h/sinC=h/sinA D. sinC/a=sin…

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asked Apr 17, 2019 181k views

2 Answers

Mariusz Jamro · Answer 1 · 2019-04-23T04:30:30+0000

We know:

sin(C)=(h)/(a)

and

sin(A)=(h)/(c)

These expressions have an
term in common. We can combine them if we can find forms of the expressions in terms of
:

h=a(sin(C))

h=c(sin(A))

Now, because
h=h (by the reflexive property), we can write:

a(sin(C))=c(sin(A))

This is our answer, A.