Question

Find area sector ACBD.... please and thank you

Answer 1

The sector is
`(360^\circ - 60^\circ)/(360^\circ) = \frac 5 6` of the circle so the area is

`\frac 5 6 \pi r^2 = \frac 5 6 \pi (10^2) = (250 \pi)/(3)`